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the ratio of the maximum velocity and maximum displacement of a particle executing simple harmonic motion is equal to omega... Explain???


3 years ago

Kshitij Sharma
33 Points
							yes, $\frac{v_{max}}{x_{max}}=\omega$  .U can derive the formula $v=\omega \sqrt{A^{2}-x^{2}}$ by phasor diagram easily.clearly for v to be max. $x^{2}$​ has to be min. so, v is max. when x=0. Hence, $v_{max}=\omega A$.and $x_{max}$ is obviosly equal to A. Hence,$\frac{v_{max}}{x_{max}}=\omega$

3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions