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Grade: 12th pass 

                        
the potential energy U(x) of a particle moving along x-axis is given by U(x) = ax-bx2 .find the equillibrium position of the particle ?
4 years ago

Answers : (1)

Vikas TU
12285 Points 
							
At eqm. position the net Force would be zero.
As, F = – dU/dx => -(a -2bx) = 0
a = 2bx
x = a/2b would be the eqm. position.
4 years ago
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