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the potential energy U(x) of a particle moving along x-axis is given by U(x) = ax-bx2 .find the equillibrium position of the particle ? the potential energy U(x) of a particle moving along x-axis is given by U(x) = ax-bx2 .find the equillibrium position of the particle ?
At eqm. position the net Force would be zero.As, F = – dU/dx => -(a -2bx) = 0a = 2bxx = a/2b would be the eqm. position.
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