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Grade 12th passMechanics

the potential energy U(x) of a particle moving along x-axis is given by U(x) = ax-bx2 .find the equillibrium position of the particle ?

Profile image of Shaima Nishar
9 Years agoGrade 12th pass
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1 Answer

Profile image of Vikas TU
9 Years ago
At eqm. position the net Force would be zero.
As, F = – dU/dx => -(a -2bx) = 0
a = 2bx
x = a/2b would be the eqm. position.