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`        The horizontal and vertical  displacements of a particle moving along a curved line are given  by x=5t and y=2t2 +t. Time after which its velocity vector makes an angle of 45 degree with the horizontal is ---------`
2 years ago

Arun
22985 Points
```							Dear Akash As at an angle of 45° both the components i.e. horizontal and vertical components of velocity should be equal as Cos45 = sin 45Hencedx/dt = dy/dt5 = 4t +14t = 4t = 1 sec.Hence after 1 sec, velocity vector will make an angle of 45°RegardsArun (askIITians forum expert)
```
2 years ago
RO
82 Points
```							 Dear Akash As at an angle of 45° both the components i.e. horizontal and vertical components of velocity should be equal as Cos45 = sin 45Hencedx/dt = dy/dt5 = 4t +14t = 4t = 1 sec.Hence after 1 sec, velocity vector will make an angle of 45°
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions