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Please tell how to solve this..A body freely falling from the rest has a velocity v after it falls through a height h. The distance it h to fall down for its velocity to become double is

Please tell how to solve this..A body freely falling from the rest has a velocity v after it falls through a height h. The distance it h to fall down for its velocity to become double is

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Grade:11

2 Answers

Arun
25750 Points
6 years ago

Dear student,

The body is falling freely under gravity, so the gravitational acceleration = a = g

The initial velocity of the body = u = 0

After covering distance = h

The velocity becomes = v

So, v2- u2 = 2gh

or v2 = 2gh

After sometime (t) its velocity becomes double = v' = 2v

Let the distance covered in time (t) = h'

Here initial velocity = v

So, v'2 - v2 = 2gh'

(2v)2- v2 = 2gh'

4v2-v2 = 2gh'

3v2  = 2gh'

3(2gh) = 2gh'

3h = h'

Thus h' is 3 times h.

Siddharth Singh
100 Points
6 years ago
1Home » Forum » Mechanics » Please tell how to solve this..A body freely...Please tell how to solve this..A body freely falling from the rest has a velocity v after it falls through a height h. The distance it h to fall down for its velocity to become double isSee Attachment 18 hours agoAnswers : (1)Dear student,The body is falling freely under gravity, so the gravitational acceleration = a = gThe initial velocity of the body = u = 0After covering distance = hThe velocity becomes = vSo, v2- u2 = 2ghor v2 = 2ghAfter sometime (t) its velocity becomes double = v` = 2vLet the distance covered in time (t) = h`Here initial velocity = vSo, v`2 - v2 = 2gh`(2v)2- v2 = 2gh`4v2-v2 = 2gh`3v2 = 2gh`3(2gh) = 2gh`3h = h`Thus h` is 3 times h.

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