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`        Please solve this problem . And give detailed explanation of all the equation involved`
2 years ago

downey zer
73 Points
```							if the mass A moves a distance x upward the pulley attached to B has to come down a distance x (since it is connected by a string)if pulley comes down a distance x , xlength of string will be freed on one side of pulley and x length of string on the other side of the pulley so 2x length of string will be freed. since the string has to be tight at all moments the mass B will move down by 2x distanceSo if A moves up by distance x B moves down by distance 2xdifferentiating twice with respect to time we find if acceleration of B =2*acceleration of Aif the string attached to B has tension T then the total tension pulling the second pulley is 2Ttherefore the tension in the string attached to A has to be 2T so that the net force on the massless pulley is zerowriting equations for A,2T – mg=ma (since a is going up)for B,mg-T=m(2a)solving these equations a=g/5but the acceleration of B =2a=2g/5did u observe one thing that tension and acceleration are  generally inversely proportional in these type of problemsthe tension on B is T but acc =2a while the acc of A =a but tension =2Thope that helps you. please approve the answer if it did
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions