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Grade 11Mechanics

Please get my these two questions solved.
If a graph of acceleration versus position is given, then how to find the equation of position with respect to time

Question image for Please get my these two questions solved. If a gr
Profile image of Prachi
9 Years agoGrade 11
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2 Answers

Profile image of Manas Shukla
9 Years ago
U dont need to draw any graph for those two questions.
We can see the maximum height of the object is at 3.5 secs.
Now we can see from given graph that we need to find h = h1 – h2
h1 = height of object at t=5secs
h2 = height of object at t= 6 secs
which can be written as h = (H - h2) – (H – h1) where H is the maximum height.
H-h1 = \frac{1}{2}gt^{2} = 5 x 1.5 x 1.5
H-h2 = 5 x 2.5 x 2.5
h = 5 (6.25 – 2.25) = 20m
 
Profile image of Manas Shukla
9 Years ago
For second question
Displacement will be = \sqrt{20^{2} + 10^{2}}
Thus X = 10\sqrt{5} = 22.36 km
Let me know if u need any further help.