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Please get my these two questions solved. If a graph of acceleration versus position is given, then how to find the equation of position with respect to time
Please get my these two questions solved. If a graph of acceleration versus position is given, then how to find the equation of position with respect to time


4 years ago

Manas Shukla
102 Points
							U dont need to draw any graph for those two questions.We can see the maximum height of the object is at 3.5 secs.Now we can see from given graph that we need to find h = h1 – h2h1 = height of object at t=5secsh2 = height of object at t= 6 secswhich can be written as h = (H - h2) – (H – h1) where H is the maximum height.H-h1 = $\frac{1}{2}gt^{2}$ = 5 x 1.5 x 1.5H-h2 = 5 x 2.5 x 2.5h = 5 (6.25 – 2.25) = 20m

4 years ago
Manas Shukla
102 Points
							For second questionDisplacement will be = $\sqrt{20^{2} + 10^{2}}$Thus X = $10\sqrt{5}$ = 22.36 kmLet me know if u need any further help.

4 years ago
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### Course Features

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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions