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Grade: 11

                        

Please get my these two questions solved. If a graph of acceleration versus position is given, then how to find the equation of position with respect to time

4 years ago

Answers : (2)

Manas Shukla
102 Points
							
U dont need to draw any graph for those two questions.
We can see the maximum height of the object is at 3.5 secs.
Now we can see from given graph that we need to find h = h1 – h2
h1 = height of object at t=5secs
h2 = height of object at t= 6 secs
which can be written as h = (H - h2) – (H – h1) where H is the maximum height.
H-h1 = \frac{1}{2}gt^{2} = 5 x 1.5 x 1.5
H-h2 = 5 x 2.5 x 2.5
h = 5 (6.25 – 2.25) = 20m
 
4 years ago
Manas Shukla
102 Points
							
For second question
Displacement will be = \sqrt{20^{2} + 10^{2}}
Thus X = 10\sqrt{5} = 22.36 km
Let me know if u need any further help.
4 years ago
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