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kinetic energy of a particle moving alog a circle of radius R depends on distance covered as T=ks 2 where k is constant. find the force acting on the particle a s function of s..

5 years ago

Answers : (1)

Sheetal
11 Points
							Given 1/2mv²=as²Differentiating both sides w.r.t. timeWe get.     Tangential accn(w1) =2as/m                   Centripetal acceleration(w2) Now net accn=√[(w1)² + (w2)²]                          √[(2as/m)² + (2as²/mR)²]                          2as/m √[1+(s/R)²]Now total force=m× net acceleration                            2as√[(1+s²/R²)]
						
3 years ago
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