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# I am having trouble solving this question:Q. A small body is projected up a rough (u=1/2) inclined plane(theeta = 60 degrees) with a speed of v=10m/s. How far along the plane does it move up before coming to rest? (g=10m/s2).Please solve this using Mechanical energy theorum:Wexternal + Wnon conservative = (Kf + Uf) – (Ki + Ui)My answer is coming out to be 21/2√3. Whereas the answer is given as 20/2√3+1

5 years ago

Nicho priyatham
625 Points

-umglcos60=mglsin60-(1/2)mv2
-(1/2)(10)(1/2)l= 10(√3/2)l-(1/2)100
so l= 20/(2√3+1)

5 years ago
Jyotinder Singh
21 Points

Thanks Nicho! That helped me out ^^! I was making a small mistake, I wasn’t multiplying friction by L. Thanks a lot! Is there an upvote system here to choose a correct reply or not? Thanks though!
5 years ago
Jyotinder Singh
21 Points

Thanks Nicho! That helped me out ^^! I was making a small mistake, I wasn’t multiplying friction by L. Thanks a lot! Is there an upvote system here to choose a correct reply or not? Thanks though!
5 years ago
Jyotinder Singh
21 Points

Thanks Nicho! That helped me out ^^! I was making a small mistake, I wasn’t multiplying friction by L. Thanks a lot! Is there an upvote system here to choose a correct reply or not? Thanks though!
5 years ago
Jyotinder Singh
21 Points

R5*TlO#L)_
5 years ago
Nicho priyatham
625 Points

ur welcome

5 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions