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Grade: 11
        
How can I solve this question: A parabolic bowl with its bottom at origin has the shape y =(x^2) /20. What is the maximum height where a bowl of mass m can be placed without slipping (x and y in metres, μ=0.5)?
one year ago

Answers : (1)

Vikas TU
6887 Points
							
Friction force would act tangentially obvious.
Hence, f = umg
Now, tanthetha = 2x/20 => x/10
sinthetha = x/root(x^2 + 100)
Hence,
mgsin(thetha) = f = umg
0.5 = x/root(x^2 + 100)
x^2/(x^2 + 100) = ¼
4x^2 = x^2 + 100
3x^2 = 100
x = 10/root(3) meter.
one year ago
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