MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        An open lift is moving  upwards with velocity 10m/s.it has an upward acceleration of 2m/s. A ball is projected upwards with velocity 20m/s relative to ground.Find (a)time when ball again meets the lift
2 years ago

Answers : (1)

Arun
23832 Points
							
Dear Himanshu
 
We can combine x = v(initial)*t + .5*a*t^2 
v(initial ball)*t + .5*a*t^2 = v(initial lift)*t + .5*a*t^2 
20t + .5(-9.8)(t^2) = 10t + .5(2)(t^2) 
10t - 4.9t^2 = t^2 
0 = 5.9t^2 -10t 
t = 1.695s 
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details