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`        An open lift is moving  upwards with velocity 10m/s.it has an upward acceleration of 2m/s. A ball is projected upwards with velocity 20m/s relative to ground.Find (a)time when ball again meets the lift`
2 years ago

Arun
23544 Points
```							Dear Himanshu We can combine x = v(initial)*t + .5*a*t^2 v(initial ball)*t + .5*a*t^2 = v(initial lift)*t + .5*a*t^2 20t + .5(-9.8)(t^2) = 10t + .5(2)(t^2) 10t - 4.9t^2 = t^2 0 = 5.9t^2 -10t t = 1.695s
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions