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`        A train of mass M=π kg is moving on a circular track of radius R with constant speed 2m/s. The length of train is half the perimeter of track. Find linear momentum of train.  `
one year ago

Arun
23478 Points
```							Consider the centre of the circle as the origin (for the X-Y Plane)Now the X-component of the linear momentum will cancel out (in the lower half and the uper half)Only the Y-component would add up.So the required momentum would be = 2∫(M/ΠR)vcosx dx {in the limit range from x= 0 to pi/2)So the Linear Momentum = 2Mv / ΠR This is general solution you can find the value according to the question
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions