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Grade 11Mechanics

a thin bar of mass m and length l is free to rotate about a fixed horizontal axis at its end. the bar is brought to a horizontal position and then released. how does the force exerted by the rod at the hinge at the axis of rotation change continuously?

Profile image of supraja venkatraman
7 Years agoGrade 11
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1 Answer

Profile image of Eshan
7 Years ago

The scenario you’re describing involves a thin bar that rotates about a fixed horizontal axis at one end after being released from a horizontal position. To understand how the force exerted by the rod at the hinge changes during this motion, we can analyze the physical principles involved, particularly focusing on torque, angular motion, and the forces acting on the bar.

The Initial Setup

When the bar is held horizontally and then released, it begins to rotate downwards due to gravitational force acting on its center of mass. The mass of the bar is evenly distributed, and the center of mass is located at the midpoint of the bar, which is at a distance of l/2 from the hinge.

The Forces at Play

At any point during the motion, there are a few key forces that need to be considered:

  • Weight of the Bar (W): This is the force acting downward due to gravity. It is calculated as W = mg, where m is the mass and g is the acceleration due to gravity.
  • Reaction Force at the Hinge (R): This force acts at the hinge and can have both horizontal and vertical components. It adjusts as the bar rotates.

Analyzing the Motion

As the bar rotates downwards, its angular velocity increases. This change in motion affects the forces acting on the bar. We can break down the analysis into two parts: the initial moment right after the release and the subsequent motion as it swings down.

Forces Right After Release

Immediately after the release, the only forces acting on the bar are its weight and the reaction force at the hinge. The bar starts from rest, so its initial angular velocity is zero. At this point, the hinge must provide a force to counteract the weight of the bar. This force can be approximated as:

R_initial = W = mg

Forces During Descent

As the bar swings downward, it accelerates due to gravity. At any angle θ from the vertical, the torque due to the weight about the hinge is:

τ = W * (l/2) * sin(θ)

This torque causes angular acceleration, which means the angular velocity of the bar increases. Hence, the kinetic energy of the system increases, and the forces at the hinge must also adjust.

Change in Hinge Force

As the bar continues to rotate, the reaction force at the hinge does not remain constant. The vertical component of the hinge force must support not only the weight of the bar but also provide the necessary centripetal force to keep the bar moving in a circular path. Therefore, as the angular velocity increases, the vertical component of the hinge force increases.

Additionally, as the bar approaches the vertical position, the centripetal force required increases, and thus the total force at the hinge can be expressed as:

R_total = W + F_c

where F_c is the centripetal force, which is related to the angular velocity (ω) of the bar:

F_c = m * (l/2) * ω²

Conclusion

In summary, the force exerted by the rod at the hinge changes continuously throughout the motion. Initially, it equals the weight of the bar. However, as the bar swings down and gains speed, the reaction force at the hinge increases to accommodate both the weight of the bar and the additional force required for centripetal acceleration. This dynamic interplay between gravitational forces and rotational motion leads to a continuously changing reaction force at the hinge.