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A shell of mass 40kg moving with a velocity of 80m/s explodes and bursts into two fragments of masses 32kg and 8kg . if the latter comes to rest, velocity of the former is
As the external force is zero so we can apply conservation of momentum lawSo40*80 = 32*v + 8*0Then v = 100 m/sHope it clears. If you like answer then please approve it.
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