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A scooter company gives the following specifications about its product:-Weight of scooter - 95 kgMaximum speed - 60 km/hrMaximum engine power - 3.5 HPPick up time to get the maximum speed - 5sCheck the validity of these specifications.
The specification given by the company are U = 0, m = 95 kg, Pm = 3.5 hp Vm = 60 km/h = 50/3 m/sec t base m = 5 sec So, the maximum acceleration that can be produced is given by, a = (50/3) – 0/5 = 10/3 So, the driving force is given by F = ma = 95 * 10/3 = 950/3 N So, the velocity that can be attained by maximum h.p. white supplying 950/3 will be V = p/F ⇒ v = 3.5 * 746 * 5/950 = 8.2 m/sec.Because, the scooter can reach a maximum of 8.s m/sec while producing a force of 950/3 N, the specifications given are some what ober claimed
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