badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

A scooter company gives the following specifications about its product:-Weight of scooter - 95 kgMaximum speed - 60 km/hrMaximum engine power - 3.5 HPPick up time to get the maximum speed - 5sCheck the validity of these specifications.

3 years ago

Answers : (1)

Arun
24742 Points
							
The specification given by the company are U = 0, m = 95 kg, Pm = 3.5 hp Vm = 60 km/h = 50/3 m/sec t base m = 5 sec So, the maximum acceleration that can be produced is given by, a = (50/3) – 0/5 = 10/3 So, the driving force is given by F = ma = 95 * 10/3 = 950/3 N So, the velocity that can be attained by maximum h.p. white supplying 950/3 will be V = p/F ⇒ v = 3.5 * 746 * 5/950 = 8.2 m/sec.Because, the scooter can reach a maximum of 8.s m/sec while producing a force of 950/3 N, the specifications given are some what ober claimed
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details