badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

A point starts moving in a straight line with a certain acceleration. At a time t after beginning of motion the acceleration suddenly becomes retardation of the same value.The time in which the point returns to the initial point is: 1) root2 t 2) (2 + root2) t 3) t/(root2) 4) Cannot be predicted

3 years ago

Answers : (1)

DR STRANGE
212 Points
							
the ans is 1) root2 t
s= ut + at2/2
let acceleration a = p
initially the velocity 0
distance d travelled in time t
d=pt2/2............(distance travelled in time t)
after time t acceleration becomes retardation i.e. a = -p
it will travel same distance d before its veloity becomes due to retardation.
therefore distance travelled is d+d= 2d
now the particle will retrace the path backward
again 
s= ut + at2/2
2d = 0t + pt’2/2
2pt2/2 = 0t + pt’2/2
t’ = root2 t
Approve if you are satisfied :)
 
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details