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A point starts moving in a straight line with a certain acceleration. At a time t after beginning of motion the acceleration suddenly becomes retardation of the same value.The time in which the point returns to the initial point is: 1) root2 t 2) (2 + root2) t 3) t/(root2) 4) Cannot be predicted
A point starts moving in a straight line with a certain acceleration. At a time t after beginning of motion the acceleration suddenly becomes retardation of the same value.The time in which the point returns to the initial point is:     1) root2 t     2) (2 + root2) t    3) t/(root2)   4) Cannot be predicted

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3 years ago

DR STRANGE
212 Points
```							the ans is 1) root2 ts= ut + at2/2let acceleration a = pinitially the velocity 0distance d travelled in time td=pt2/2............(distance travelled in time t)after time t acceleration becomes retardation i.e. a = -pit will travel same distance d before its veloity becomes due to retardation.therefore distance travelled is d+d= 2dnow the particle will retrace the path backwardagain s= ut + at2/22d = 0t + pt’2/22pt2/2 = 0t + pt’2/2t’ = root2 tApprove if you are satisfied :)
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3 years ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions