A particle is projected from the bottom of an inclined plane of inclination 30° with velocity of 40 m/s at an angle of 60° with horizontal. Find the speed of the particle when its velocity vector is parallel to the plane.

Question

Vikas TU · Answer

Hiii Horizontal component of velocity remais constant , so, 40cos60 = vcos30 solve for v v = 40/sqrt3 m/sec

Khimraj · Answer

Horizontal component of velocity always remains constant ∴ 40 cos 60 ∘ = v cos 30 ∘ or v = 40/ √ 3 m / s . ....................................................................................

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A particle is projected from the bottom of an inclined plane of inclination 30° with velocity of 40 m/s at an angle of 60° with horizontal. Find the speed of the particle when its velocity vector is parallel to the plane.

A particle is projected from the bottom of an inclined plane of inclination 30° with velocity of 40 m/s at an angle of 60° with horizontal. Find the speed of the particle when its velocity vector is parallel to the plane.

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A particle is projected from the bottom of an inclined plane of inclination 30° with velocity of 40 m/s at an angle of 60° with horizontal. Find the speed of the particle when its velocity vector is parallel to the plane.

A particle is projected from the bottom of an inclined plane of inclination 30° with velocity of 40 m/s at an angle of 60° with horizontal. Find the speed of the particle when its velocity vector is parallel to the plane.

2 Answers

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Other Related Questions on Mechanics

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