A particle executes simple harmonic motion with an amplitude of 10 cm. At what distance from the mean position are the kinetic and potential energies equal?
Simran Bhatia , 10 Years ago
Grade 11
1 Answers
Aditi Chauhan
Last Activity: 10 Years ago
Sol. . r = 10cm
Because, K.E. = P.E.
So (1/2) m ω2 (r2– y2) = (1/2) m ω2y2
r2 – y2 = y2 ⇒ 2y2 = r2 ⇒ y = r/√2 = 10/√2 = 5√2 cm form the mean position
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