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A particle doing simple harmonic motion whose amplitude is 4cm,time period is 12 sec.the ratio between time taken by it in going from its mean position to 2 cm and 2 cm to extreme position is

Srinivas , 8 Years ago

Grade 11

1 Answers

Arun

y = 4 sin(2 pi/12)*t

Now y = 2

2 = 4 sin(pi/6) *t₁

1/2 = sin(pi/6) *t₁

Pi/6 = (pi/6)* t₁

t₁ = 1 sec

Hence T1 = t1 - 0 = 1 sec

Now, similarily

Put y = 4

You will get t₂ = 3 sec.

Hence T2 = t2 - t1 = 3- 1 = 2 sec

Hence

T₁ : T₂ = 1:2

Last Activity: 8 Years ago

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Mechanics> A particle doing simple harmonic motion w...

A particle doing simple harmonic motion whose amplitude is 4cm,time period is 12 sec.the ratio between time taken by it in going from its mean position to 2 cm and 2 cm to extreme position is

Srinivas , 8 Years ago

Arun

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