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A particle doing simple harmonic motion whose amplitude is 4cm,time period is 12 sec.the ratio between time taken by it in going from its mean position to 2 cm and 2 cm to extreme position is
y = 4 sin(2 pi/12)*tNow y = 22 = 4 sin(pi/6) *t11/2 = sin(pi/6) *t1Pi/6 = (pi/6)* t1t1 = 1 secHence T1 = t1 - 0 = 1 sec Now, similarilyPut y = 4You will get t2 = 3 sec.Hence T2 = t2 - t1 = 3- 1 = 2 secHenceT1 : T2 = 1:2
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