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`        A man hangs from a horizontal bar with his arms at right angles to each other. If the weight of the man is 69kg the tension in each arm is 1) 60 kg wt 2) 60√2 3) 30`
one year ago

Rama sai rohan
32 Points
```							If we draw fbd for the man we find that mg acts down . If you resolve the tension act on hands you get up ward force is equal to 2Tcosx where x=45°.As he is in rest upward force equal to downward force.                  2Tcos45°=690N                  T√2=690N                   T=690/√2N                   T =34.5√2×10N                    T=34.5√2kgwt
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions