Grade 11Mechanics

A hunter in a valley is trying to shoot a deer on a hill. The distance of the deer along his line of sight is 10(181)^½meters and the height of the hill is 90 meters. His gun has a muzzle velocity of 100 m/sec. Minimum how many meters above the deer should he aim his rifle in order to hit it? [g=10 m/s^2]

Anwesha Barman

9 Years agoGrade 11

3 Answers

Vikas TU

Approved Tutor Answer9 Years ago

Apply second law of eqn. in y- direcn. .i.e.

90 = 100*t – 0.5*g*t^2

solving we get t=1 and t= 19 s but t= 1 is perceived.

In this 1 s he would miss the deer.

So to hit it, he needs extra => 0.5*g*1^1 = 5 meter above the deer.

Pushkar prabhat

9 Years ago

Height of hill=90m,. u=100m/s ,g=-10m/s2 s=ut+1/2gt2 _eq(1). here we find `t` it is =1or 19 s then we find minimum meter above form eq(1) s=5m

Vibekjyoti Sahoo

4 Years ago

Apply second law of eqn. in y- direcn. .i.e.

90 = 100*t – 0.5*g*t^2

solving we get t=1 and t= 19 s but t= 1 is perceived.

In this 1 s he would miss the deer.

So to hit it, he needs extra => 0.5*g*1^1 = 5 meter above the deer

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Anwesha Barman

3 Answers

Vikas TU

Pushkar prabhat

Vibekjyoti Sahoo

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