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Grade: 11

                        

A hunter in a valley is trying to shoot a deer on a hill. The distance of the deer along his line of sight is 10(181) ½ meters and the height of the hill is 90 meters. His gun has a muzzle velocity of 100 m/sec. Minimum how many meters above the deer should he aim his rifle in order to hit it? [g=10 m/s 2]

4 years ago

Answers : (2)

Vikas TU
12133 Points
							
Apply second law of eqn. in y-  direcn. .i.e.
90 = 100*t – 0.5*g*t^2
solving we get t=1 and t= 19 s but t= 1 is perceived.
In this 1 s he would miss the deer.
So to hit it, he needs extra => 0.5*g*1^1 = 5 meter above the deer.
4 years ago
Pushkar prabhat
11 Points
							Height of hill=90m,. u=100m/s ,g=-10m/s2    s=ut+1/2gt2 _eq(1).  here we find `t` it is =1or 19 s then we find minimum meter above  form eq(1) s=5m
						
3 years ago
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  • NCERT Solutions
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  • Previous Year Exam Questions


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