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Grade: 11
        
A body of mass 1kg is moving on the x axis under the action of a force such that its variation of PE as a function of time is given by U=x-x^2.Find its (1)equilibrium position and tell its nature
(2)velocity at equilibrium position if its velocity at origin is 2m/s.
2 years ago

Answers : (2)

Arun
23478 Points
							
Dear student
 
At equilibrium position
dU/dx should be zero
1 - 2x = 0
Hence
x = 1/2 metres

Regards
Arun (askIITians forum expert)
2 years ago
prasad
21 Points
							
plz also find the velocity at equlibrium position if its velocity at origin is 2m/s.
2 years ago
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