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`        A body of mass 1kg is moving on the x axis under the action of a force such that its variation of PE as a function of time is given by U=x-x^2.Find its (1)equilibrium position and tell its nature(2)velocity at equilibrium position if its velocity at origin is 2m/s.`
2 years ago

Arun
23478 Points
```							Dear student

At equilibrium position
dU/dx should be zero
1 - 2x = 0
Hence
x = 1/2 metres
Regards
```
2 years ago
21 Points
```							plz also find the velocity at equlibrium position if its velocity at origin is 2m/s.
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions