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body A has mass of 1 kg and location (1,2)
body B has mass of 2kg and location (-1,3)
mcxc = m1x1 + m2x2
(1+2) xc = (1*1) + (2*-1)
xc = -1/3
similarly
mc yc = m1 y1 + m2 y2
(1=2) yc = (1*2)+(2*3)
yc= 8/3
hence the co-ordinates of the center of mass are ( -1/3 , 8/3)
Regards
Arun (askIITians forum expert)
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