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`        A body having a mass of 5 kg starts from rest and attains a speed of 4mpersec in 6 seconds find the force required to move the body wwith uniform acceleration in ahorizontal surface take coefficent of friction as 0.25`
3 years ago

## Answers : (1)

Vikas TU
10364 Points
```							From Newton’s First law of eqn. we get,v = u +at4 = 0 + a*6a = 2/3 m/s^2Force required = m*a => 5*2/3 = 10/3 N => 3.33 NFriction force = 0.25*50 => 25/2 = 12.5 NNet force => 12.5 – 3.33 => 9.22 approx.
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions