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`        a body falls freely from rest and has velocity v after it falls through height h the distance it has to fall down father from its velocity to become double`
one year ago

Arun
22545 Points
```							For first 2 m,
v^2 = 0^2 + 2g*h
v^2 = 2gh
After that let it traverse d m futher more when its v becomes double .i.e. 2v
(2v)^2 = v^2 + 2gd
2gd = 3v^2
d = 3v^2/2g
put the value of v^2
d = 3*2gh/2g = 3h meter.

Regards

```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions