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Grade: 12
`        A body dropped freely from a height H travels 36 percent of total diatmce during the last second. Then H is equal to`
one year ago

## Answers : (1)

Arun
22533 Points
```							Let H be the height of the building and t be the time to fall through this height H. Then H = ½ g t^2 = 5 t^2.  ---- (1) In (t-1) second the distance traveled is 1 - 0.36 H = 0.64 H. 0.64 H = 5 (t-1)^2.    ------(2) (2) / (1) gives 0.64 = (t-1)^2/ t^2 Or 0.8 = (t-1) / t Solving we get t= 5 second. Using (1) we get H = 125 m.

Regards
Arun (askIITians forum expert)
```
one year ago
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