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Grade: 12th pass

                        

A block of wood floats in water with 0.546 of its volume submerged. In oil it has 0.918 of its volume submerged. Find the density of (a).the wood (b).the oil.

one month ago

Answers : (1)

Vikas TU
13786 Points
							
Dear student 
Let density of wood be x 
For floating in water 
ρbvg = 0.546 * dw * g 
For floating in oil 
ρbvg = 0.918*doil*g 
so, doil/dw = 0.546/0.918 
So, doil / dw = 91/153 
Hope this will help 
Good Luck 
Cheers 
one month ago
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