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A block of wood floats in water with 0.546 of its volume submerged. In oil it has 0.918 of its volume submerged. Find the density of (a).the wood (b).the oil.
Dear student Let density of wood be x For floating in water ρbvg = 0.546 * dw * g For floating in oil ρbvg = 0.918*doil*g so, doil/dw = 0.546/0.918 So, doil / dw = 91/153 Hope this will help Good Luck Cheers
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