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Grade: 11
        

a block of mass 5 kg is raised from the bottom of a lake to a ht of 3m without change in KE. if density of block is 3000kg/m3 then find the work done.


 


 


 


 


ANS 100J

6 years ago

Answers : (3)

Harsh Srivastava
34 Points
							Work done by whom?
						
6 years ago
rohan
20 Points
							to raise the block
						
6 years ago
Pawan Singh
13 Points
							Hey, answer for your question is.... Given that, Mass of block = 5 kg. Density of block = 3000 kg/m3 So, Volume of block = 5/3000 = 1/600 m3 Now mass of the water displaced by block = 1000*1/600 = 5/3 kg. Effective mass of block inside water = 5 - 5/3 = 10/3 kg Hence, work done in raising the block by 3m = (10/3)*10*3 = 100 joule.. Hope, this will be helpful for you. Thank you
						
2 years ago
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Course Features

  • 110 Video Lectures
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  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


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