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Grade 11Mechanics

A block of mass 2 kg is on a horizontal surface the cofficient of Static and kinetic friction are 0.6 and 0.2 the minimum horizontal force required to start the motion is applied and if it is continued the velocity acquired by the body at the end of the two seconds is( g= 10 ms^2)

Profile image of Harshita
7 Years agoGrade 11
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Profile image of Arun
ApprovedApproved Tutor Answer7 Years ago
M=20kgmuMg = 2 * 10 * 0.6 (static Smax)= 12N force is applied to the blockmuMg = 2 * 10 * 0.2 (kinetic)=4NFnet = F-fr = 12 - 4 = 8NF/m=8/2= 4 m/s2#use v=u+at u= 0, a=4 , t= 2 Final velocity will be 8m/s
 
 
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Arun