0

Guest

Courses New

A ball loses 15% of its kinetic energy after it bounces back from a concrete slab . The speed with which one must throw to have it. Bounce back to same height ‘h’ is . Here h is equal to 12.4 m . Kindly give explanation to each step you do

A ball loses 15% of its kinetic energy after it bounces back from a concrete slab . The speed with which one must throw to have it. Bounce back to same height ‘h’ is . Here h is equal to 12.4 m . Kindly give explanation to each step you do
 

Grade:11

2 Answers

Arun
25750 Points
4 years ago
Dear Vansh
 
I have attached an image containing solution. Please check and let me know if any difficulty arises.
 
232-877_1.PNG
 
Regards
Arun
Khimraj
3007 Points
4 years ago
Since the ball will bounce back to the same height Ui = Uf,

0.85 (Ki + Ui) = Uf

0.85 (Ki + Uf) = Uf

Ki = (0.15 * Uf) / 0.85

½ mvi^2 = (0.15 * mgh) / 0.85

vi = square root of [(0.15 * 2 * m * g * h) / (0.85 * m)]

vi = square root of [(0.15 * 2 * 9.8 * h) / ( 0.85)]

vi =  square root of [ 3.45 * 12.4] = 6.54

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More