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Grade: 11
        
A ball loses 15% of its kinetic energy after it bounces back from a concrete slab . The speed with which one must throw to have it. Bounce back to same height ‘h’ is . Here h is equal to 12.4 m . Kindly give explanation to each step you do
 
one month ago

Answers : (2)

Arun
22331 Points
							
Dear Vansh
 
I have attached an image containing solution. Please check and let me know if any difficulty arises.
 
232-877_1.PNG
 
Regards
Arun
one month ago
Khimraj
3008 Points
							
Since the ball will bounce back to the same height Ui = Uf,

0.85 (Ki + Ui) = Uf

0.85 (Ki + Uf) = Uf

Ki = (0.15 * Uf) / 0.85

½ mvi^2 = (0.15 * mgh) / 0.85

vi = square root of [(0.15 * 2 * m * g * h) / (0.85 * m)]

vi = square root of [(0.15 * 2 * 9.8 * h) / ( 0.85)]

vi =  square root of [ 3.45 * 12.4] = 6.54
one month ago
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