A 7.96-kg block rests on a plane inclined at 22.0° to the horizontal, as shown in Fig. The coefficient of static friction is 0.25, while the coefficient of kinetic friction is 0.15. (a) What is the minimum force F, parallel to the plane, that will prevent the block from slipping down the plane? (b) What is the minimum force F that will start the block moving up the plane? (c) What force F is required to move the block up the plane at constant velocity?

Question

Aditi Chauhan · Answer

Round off to three significant figures,
F_min = 11.3 N
Therefore, the minimum value of $\overrightarrow{F}$ that will prevent the block from slipping down the plane is 11.3 N .

Round off to three significant figures,
F = 40.1 N
Therefore, the force F which will move the block upward with constant velocity is 41.1 N.

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