badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

A 7.96-kg block rests on a plane inclined at 22.0° to the horizontal, as shown in Fig. The coefficient of static friction is 0.25, while the coefficient of kinetic friction is 0.15. (a) What is the minimum force F, parallel to the plane, that will prevent the block from slipping down the plane? (b) What is the minimum force F that will start the block moving up the plane? (c) What force F is required to move the block up the plane at constant velocity?

5 years ago

Answers : (1)

Aditi Chauhan
askIITians Faculty
396 Points
							236-1155_1.PNG
Round off to three significant figures,
Fmin = 11.3 N
Therefore, the minimum value of \overrightarrow{F}that will prevent the block from slipping down the plane is 11.3 N .
236-478_1.PNG
236-1061_1.PNG
Round off to three significant figures,
F = 40.1 N
Therefore, the force F which will move the block upward with constant velocity is 41.1 N.

5 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details