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Grade: 12th pass
        
A 1780 kg unmanned space probe is moving in a straight line at a constant speed of 349 m/s. Control rockets on the space probe execute a burn in which a thrust of 3940 N acts for 82.1 s. (a) What is the change in the magnitude of the probe's linear momentum if the thrust is directed in the forward direction, so as to slow the probe? (b)What is the change in kinetic energy under the same condition? Assume that the mass of the ejected burn products is negligible compared to the mass of the space probe.
 
one year ago

Answers : (1)

Arun
23374 Points
							
To find out the change in momentum of the probe, substitute 3940 N for the net force F and 82.1 s for the time interval Δt in the equation Δp = F Δt,Δp = F Δt= (3940 N) (82.1 s)=323474 N. s …… (3)From equation (3) we observed that, change in momentum of the probe would be 323474 N. s.The direction of thrust respect to the velocity will not matter for this problem. Therefore the change in momentum of the probe is equal in the every case for the thrust is backward, forward and sideways.
one year ago
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  • Discussion Forum
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