0

Guest

Courses New

A 1200-kg car is being towed up an 18° incline by means of a rope attached to the rear of a truck. The rope makes an angle of 27° with the incline. What is the greatest distance that the car can be towed in the first 7.5 s starting from rest if the rope has a breaking strength of 4.6 kN? Ignore all resistive forces on the car. See Fig.

A 1200-kg car is being towed up an 18° incline by means of a rope attached to the rear of a truck. The rope makes an angle of 27° with the incline. What is the greatest distance that the car can be towed in the first 7.5 s starting from rest if the rope has a breaking strength of 4.6 kN? Ignore all resistive forces on the car. See Fig.

Grade:11

1 Answers

Aditi Chauhan
askIITians Faculty 396 Points
9 years ago
236-2115_1.PNG
236-1364_1.PNG
Therefore, the distance by which the car can move in 7.5 s is 10.8 m.

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More