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satendra Grade: 12th pass
        
 A 0.1kg mass is suspended from a wire of negligible mass. The length of the wire is 1m and its cross-sectional area is 4.9*10-7m2. If the mass is pulled a little in the vertically downward direction and released, it performs simple harmonic motion of angular frequency 140 rad s -1. If the Young’s modules of the material of the wire is n*109Nm-2, the value of n is.
3 years ago

Answers : (1)

Aditi Chauhan
askIITians Faculty
396 Points
										

We know that 8 = vK/m ……..(i)

Here Y = FL/Al ? F = (YA/L)l

Comparing the above equations with F = kl we get

K= (YA/L) ………….(ii)

From (i) & (ii), ? = v YA/ml

? 140 = vn*109 * 4.9 * 10-7/0.1 * 1

? n =4

3 years ago
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