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A particle mass 10 gm is executing shm with an amplitude of 0.5 m and periodic time of pi/s secThe max value of the force acting on the particle

pallavi pradeep bhardwaj , 15 Years ago
Grade 12
anser 2 Answers
Badiuddin askIITians.ismu Expert

Last Activity: 15 Years ago

Dear pallavi

x=Xsinwt         where w=2 pi/T          and T=pi/5

 =.5sin 10t

w=√k/m

so k=w2m

       =102 *10

        =1000   gm/sec2

maximum force=kx

                       =1000*.5  m*gm/sec2

                        =.5 kg m/sec2


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Askiitians Expert Bharath-IITD

Last Activity: 15 Years ago

Dear Pallavi,

We know for shm motion of the particle  its displacement is given by y= y0 sin ωt  Where  ω = 2π/T =  2π/π = 2 and amplitude

y0 = 0.5 m

thus aceeleration on the particle is given by a=  d2y/d2t =   - y0 * ω2 * sin ωt

Maximum acceleration is amax = - y0 * ω2  = - 2 m/s2

Thus maximum force in magnitude = | m* amax| = 0.02 N

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Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We
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Adapa Bharath

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