# A particle mass 10 gm is executing shm with an amplitude of 0.5 m and periodic time of pi/s secThe max value of the force acting on the particle

148 Points
14 years ago

Dear pallavi

x=Xsinwt         where w=2 pi/T          and T=pi/5

=.5sin 10t

w=√k/m

so k=w2m

=102 *10

=1000   gm/sec2

maximum force=kx

=1000*.5  m*gm/sec2

=.5 kg m/sec2

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23 Points
14 years ago

Dear Pallavi,

We know for shm motion of the particle  its displacement is given by y= y0 sin ωt  Where  ω = 2π/T =  2π/π = 2 and amplitude

y0 = 0.5 m

thus aceeleration on the particle is given by a=  d2y/d2t =   - y0 * ω2 * sin ωt

Maximum acceleration is amax = - y0 * ω2  = - 2 m/s2

Thus maximum force in magnitude = | m* amax| = 0.02 N

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