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A particle mass 10 gm is executing shm with an amplitude of 0.5 m and periodic time of pi/s secThe max value of the force acting on the particle
Dear pallavi
x=Xsinwt where w=2 pi/T and T=pi/5
=.5sin 10t
w=√k/m
so k=w2m
=102 *10
=1000 gm/sec2
maximum force=kx
=1000*.5 m*gm/sec2
=.5 kg m/sec2
Dear Pallavi,
We know for shm motion of the particle its displacement is given by y= y0 sin ωt Where ω = 2π/T = 2π/π = 2 and amplitude
y0 = 0.5 m
thus aceeleration on the particle is given by a= d2y/d2t = - y0 * ω2 * sin ωt
Maximum acceleration is amax = - y0 * ω2 = - 2 m/s2
Thus maximum force in magnitude = | m* amax| = 0.02 N
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