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# A mass m=100gm is attached at the end of  a light spring which oscillates on a fictionless horizontal table with an amplitude equal to 0.16m and time period equal to 2sec Initially the mass is released from rest at t=0 and displacement x=-0.16m the expression for the displacement of the mass at any time t is

147 Points
11 years ago

Dear Pallavi

Equation of SHM is given as

x=X sin(wt + Φ)

where  X=.16 m

w=2∏/T

=2∏/2

=∏

so x=.16 sin(∏t + Φ)

given at t=0 sec   x=-.16m

-.16= .16sin(0 + Φ)

or sin( Φ) = -1

or  Φ =-∏/2

so final equation is

x=.16 sin(∏t -∏/2)

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