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A mass m=100gm is attached at the end of a light spring which oscillates on a fictionless horizontal table with an amplitude equal to 0.16m and time period equal to 2sec Initially the mass is released from rest at t=0 and displacement x=-0.16m the expression for the displacement of the mass at any time t is

A mass m=100gm is attached at the end of  a light spring which oscillates on a fictionless horizontal table with an amplitude equal to 0.16m and time period equal to 2sec Initially the mass is released from rest at t=0 and displacement x=-0.16m the expression for the displacement of the mass at any time t is

Grade:12

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear Pallavi

Equation of SHM is given as

x=X sin(wt + Φ)   

  where  X=.16 m

  w=2∏/T

    =2∏/2

     =∏

so x=.16 sin(∏t + Φ)  

given at t=0 sec   x=-.16m

-.16= .16sin(0 + Φ) 

or sin( Φ) = -1

   or  Φ =-∏/2

so final equation is

x=.16 sin(∏t -∏/2)


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