Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Thw two block m = 5kg and M=25kg as shown are free to move. The co-efficient of friction between the blocks is µ s = 0.4 , but the co-efficient of friction between the ground and M is frictionless. What is the minimum horizontol force F required to hold m against M ?
For the block with mass m not to slide down, μR = mg, where R = minimum force of action/reaction between the blocks => R = 125N=> minimum acceleration of the larger block a = 125/(25) m/s^2 => F (minimum) = (m+M)a = (30) * 5 =150NAnswer by: techtocore.com.co.in
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -