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Thw two block m = 5kg and M=25kg as shown are free to move. The co-efficient of friction between the blocks is µ s = 0.4 , but the co-efficient of friction between the ground and M is frictionless. What is the minimum horizontol force F required to hold m against M ? Thw two block m = 5kg and M=25kg as shown are free to move. The co-efficient of friction between the blocks is µs = 0.4 , but the co-efficient of friction between the ground and M is frictionless. What is the minimum horizontol force F required to hold m against M ?
Thw two block m = 5kg and M=25kg as shown are free to move. The co-efficient of friction between the blocks is µs = 0.4 , but the co-efficient of friction between the ground and M is frictionless. What is the minimum horizontol force F required to hold m against M ?
For the block with mass m not to slide down, μR = mg, where R = minimum force of action/reaction between the blocks => R = 125N=> minimum acceleration of the larger block a = 125/(25) m/s^2 => F (minimum) = (m+M)a = (30) * 5 =150NAnswer by: techtocore.com.co.in
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