Thw two block m = 5kg and M=25kg as shown are free to move. The co-efficient of friction between the blocks is µ_{s = 0.4 , but the co-efficient of friction between the ground and M is frictionless. What is the minimum horizontol force F required to hold m against M ?}

Question

Akash Ravi · Answer

For the block with mass m not to slide down,
μR = mg, where R = minimum force of action/reaction between the blocks
=> R = 125N
=> minimum acceleration of the larger block
a = 125/(25) m/s^2
=> F (minimum)
= (m+M)a
= (30) * 5

=150N

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Thw two block m = 5kg and M=25kg as shown are free to move. The co-efficient of friction between the blocks is µ s = 0.4 , but the co-efficient of friction between the ground and M is frictionless. What is the minimum horizontol force F required to hold m against M ?

Thw two block m = 5kg and M=25kg as shown are free to move. The co-efficient of friction between the blocks is µ_{s = 0.4 , but the co-efficient of friction between the ground and M is frictionless. What is the minimum horizontol force F required to hold m against M ?}

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Thw two block m = 5kg and M=25kg as shown are free to move. The co-efficient of friction between the blocks is µ s = 0.4 , but the co-efficient of friction between the ground and M is frictionless. What is the minimum horizontol force F required to hold m against M ?

Thw two block m = 5kg and M=25kg as shown are free to move. The co-efficient of friction between the blocks is µs = 0.4 , but the co-efficient of friction between the ground and M is frictionless. What is the minimum horizontol force F required to hold m against M ?

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Thw two block m = 5kg and M=25kg as shown are free to move. The co-efficient of friction between the blocks is µ_{s = 0.4 , but the co-efficient of friction between the ground and M is frictionless. What is the minimum horizontol force F required to hold m against M ?}