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Thw two block m = 5kg and M=25kg as shown are free to move. The co-efficient of friction between the blocks is µ s = 0.4 , but the co-efficient of friction between the ground and M is frictionless. What is the minimum horizontol force F required to hold m against M ?

Thw two block m = 5kg and M=25kg as shown are free to move. The co-efficient of friction between the blocks is µs = 0.4 , but the co-efficient of friction between the ground and M is frictionless. What is the minimum horizontol force F required to hold m against M ?


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Grade:11

1 Answers

Akash Ravi
18 Points
9 years ago
For the block with mass m not to slide down, 
μR = mg, where R = minimum force of action/reaction between the blocks 
=> R = 125N
=> minimum acceleration of the larger block 
a = 125/(25) m/s^2 
=> F (minimum) 
= (m+M)a 
= (30) * 5 
=150N
Answer by: techtocore.com.co.in
 

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