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The relation 3t=(3x)^1/2 + 6 describes the displacement of a particle in one direction where x is in metres and t is in seconds.The displacement when the velocity is zero is:-
Hi Divya Thakur 3t=(3x)^1/2 + 6 simplify the expression x=(1/3)(3t-6)^2.........(1) for velocity diffrentiate v=dx/dt=(2/3)(3t-6)*3 =6t-12 for v=0 6t-12=0 or t=2 put value of t in equation 1 x=0 for t<2 motion is not define motion is just started after t>=2 at this point displacement as well as velocity is zero Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best Divya. Regards, Askiitians Experts Badiuddin
Hi Divya Thakur
3t=(3x)^1/2 + 6
simplify the expression
x=(1/3)(3t-6)^2.........(1)
for velocity diffrentiate
v=dx/dt=(2/3)(3t-6)*3
=6t-12
for v=0
6t-12=0
or t=2
put value of t in equation 1
x=0
for t<2 motion is not define
motion is just started after t>=2
at this point displacement as well as velocity is zero
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best Divya. Regards, Askiitians Experts Badiuddin
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