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The relation 3t=(3x)^1/2 + 6 describes the displacement of a particle in one direction where x is in metres and t is in seconds.The displacement when the velocity is zero is:-

The relation 3t=(3x)^1/2 + 6 describes the displacement of a particle in one direction where x is in metres and t is in seconds.The displacement when the velocity is zero is:-

Grade:12

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Hi Divya Thakur

3t=(3x)^1/2 + 6

simplify the expression

x=(1/3)(3t-6)^2.........(1)

for velocity diffrentiate

v=dx/dt=(2/3)(3t-6)*3

                =6t-12

for v=0

  6t-12=0

    or t=2

put value of t in equation 1

x=0

for t<2 motion is not define

motion is just started after t>=2

at this point displacement as well as velocity is zero


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 All the best Divya.
 
Regards,
Askiitians Experts
Badiuddin



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