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# The relation 3t=(3x)^1/2 + 6 describes the displacement of a particle in one direction where x is in metres and t is in seconds.The displacement when the velocity is zero is:-

147 Points
11 years ago

Hi Divya Thakur

3t=(3x)^1/2 + 6

simplify the expression

x=(1/3)(3t-6)^2.........(1)

for velocity diffrentiate

v=dx/dt=(2/3)(3t-6)*3

=6t-12

for v=0

6t-12=0

or t=2

put value of t in equation 1

x=0

for t<2 motion is not define

motion is just started after t>=2

at this point displacement as well as velocity is zero

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All the best Divya.

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