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if a body of mass m collides with a body of mass 2m it changes its direction of motion but when it collides with a body of mass m it stops and when it collides with a body of mass m/2 it does not changes its direction of motion but there is only change in speed.prove the thirs case with the help of newton thirs law.please reply fast.

Rajneesh Pujani , 14 Years ago
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anser 1 Answers
Askiitians Tutor Team

To analyze the scenario you presented, we can apply Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction. This principle helps us understand how different masses interact during collisions. Let's break down the third case where a body of mass \( m \) collides with a body of mass \( \frac{m}{2} \) and examine why the first body does not change its direction but experiences a change in speed.

Understanding the Collision

In this case, we have two bodies: one with mass \( m \) (let's call it Body A) and another with mass \( \frac{m}{2} \) (Body B). When Body A collides with Body B, we need to consider the conservation of momentum and the forces acting during the collision.

Initial Momentum

Before the collision, let's assume Body A is moving with an initial velocity \( v \) and Body B is at rest. The total initial momentum \( p_{\text{initial}} \) of the system can be expressed as:

  • Initial momentum of Body A: \( mv \)
  • Initial momentum of Body B: \( 0 \)

Thus, the total initial momentum is:

pinitial = mv + 0 = mv

During the Collision

When Body A collides with Body B, according to Newton's Third Law, Body A exerts a force on Body B, and simultaneously, Body B exerts an equal and opposite force on Body A. This interaction causes Body A to slow down, while Body B starts to move in the direction of Body A's initial motion.

Final Momentum

Let’s denote the final velocity of Body A after the collision as \( v' \) and the final velocity of Body B as \( u \). According to the conservation of momentum, the total momentum after the collision must equal the total momentum before the collision:

pfinal = mv' + \frac{m}{2}u

Setting the initial momentum equal to the final momentum gives us:

mv = mv' + \frac{m}{2}u

Analyzing the Velocities

Since Body B has half the mass of Body A, it will accelerate more than Body A will decelerate due to the force exerted during the collision. If we assume that Body A does not reverse direction but simply slows down, we can analyze the velocities further.

For Body A to stop changing direction, the force exerted by Body B must not be enough to overcome the inertia of Body A significantly. Instead, Body A will lose some speed, while Body B gains speed. The exact relationship between the velocities can be derived from the equations of motion, but qualitatively, we can say:

  • Body A slows down due to the force exerted by Body B.
  • Body B starts moving in the same direction as Body A, gaining speed.

Conclusion of the Analysis

In this collision, Body A does not change its direction because the mass of Body B is significantly smaller, resulting in a smaller change in momentum for Body A. Instead, Body A experiences a decrease in speed while Body B accelerates in the same direction. This scenario illustrates how the interaction between different masses during a collision can lead to varying outcomes based on their relative sizes and the forces involved.

Thus, we have demonstrated that when a body of mass \( m \) collides with a body of mass \( \frac{m}{2} \), it does not change its direction of motion but only its speed, in accordance with Newton's Third Law of Motion and the principles of momentum conservation.

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