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A BLOCK OF MASS 2kg. PLACED ON A LONG HORIZONTAL FRICTIONLESS TABLE IS PULLED HORIZONTALLY BY A CONSTANT FORCE F.IT IS FOUND TO MOVE 10m. IN FIRST TWO SECONDS. FIND THE MAGNITUDE OF F?
since the table is frictionless,there is no opposing frictional force acting upon the block during its motion.
u=0 and t=2s and accn. of block a=F/m=F/2
then,
s=ut+1/2 at2
10=(0)2 +1/2 (F/2)(2)2
F=10N.
Force = f
Mass = 2kg
Acc. = force/mass = f/2
s = ut + 1/2 X at X t
so 10 = 0 + 1/2 X f/2 X 4
so Force = 10N
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