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TWO PARTICLES OF MASS M ARE TIED AT THE END OF A LIGHT STRING OF LENGTH 2a AND IS KEPT ON A FRICTIONLESS SURFACE WITH STRING HELD TIGHT SO THAT EACH MASS IS AT A DISTANCE a FROM CENTRE. NOW MID POINT IS PULLED VERTICALLY UPWARDS WITH A FORCE F . THUS PARTICLES MOVE TOWARDS EACH OTHER ON SURFACE. THE MAGNITUDE OF ACCLERATION WHEN SEPERATION BETWEEN THEM IS 2X

TWO PARTICLES OF MASS M ARE TIED AT THE END OF A LIGHT STRING  OF LENGTH 2a  AND IS KEPT ON A FRICTIONLESS SURFACE WITH STRING HELD TIGHT SO THAT EACH MASS IS AT A DISTANCE a  FROM CENTRE. NOW MID POINT IS PULLED VERTICALLY UPWARDS  WITH A FORCE F . THUS PARTICLES MOVE TOWARDS EACH OTHER ON SURFACE. THE MAGNITUDE OF ACCLERATION WHEN SEPERATION BETWEEN THEM IS 2X

Grade:12th Pass

1 Answers

Aman Bansal
592 Points
10 years ago

Dear Pankaj,

The answer to your problem is : 

F/2m * x/(x2-a2)1/2

Best Of luck

Plz Approve the answer...!!!!

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