TWO PARTICLES OF MASS M ARE TIED AT THE END OF A LIGHT STRING OF LENGTH 2a AND IS KEPT ON A FRICTIONLESS SURFACE WITH STRING HELD TIGHT SO THAT EACH MASS IS AT A DISTANCE a FROM CENTRE. NOW MID POINT IS PULLED VERTICALLY UPWARDS WITH A FORCE F . THUS PARTICLES MOVE TOWARDS EACH OTHER ON SURFACE. THE MAGNITUDE OF ACCLERATION WHEN SEPERATION BETWEEN THEM IS 2X

Dear Pankaj,

The answer to your problem is : 

F/2m * x/(x²-a²)^1/2

Best Of luck

Plz Approve the answer...!!!!

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