A ball is projected from a point 45m high, along the horizontal with speed 20m/s. if the ball perpendicularly strikes a plane inclined at angle theta with the horizontal. find tan(theta) [g=10m/s² ]

dear chaitanya,

As the projectile is projected , the horizontal or the y component remains the same ( we have neglected air resistance )

but the x component will increase due to acc due to gravity,

therefore , v² = u² + 2as

u=0

a=10m/s²

 s=45 m

therefore v= 30 m/s ,

as we know that  tan(theta) = v(along y component) / v( along x component)

tan(theta) = -2/3

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