Q.A particle moves from rest at A on the surface of a smooth cylinder of radius r as shown.At B it leaves the cylinder.The equation relating alpha and beta is

a.)3sin(alpha)=2cos(beta)

b.)2sin(alpha)=3cos(beta)

c.) 3sin(beta)=2cos(alpha)

d.)2sin(beta)=3cos(alpha)

Question

Q.A particle moves from rest at A on the surface of a smooth cylinder of radius r as shown.At B it leaves the cylinder.The equation relating alpha and beta is

a.)3sin(alpha)=2cos(beta)

b.)2sin(alpha)=3cos(beta)

c.) 3sin(beta)=2cos(alpha)

d.)2sin(beta)=3cos(alpha)

vikas askiitian expert · Answer

let the horizonta lsurface of sphere is at zero potential....radius of sphere os R...

at point A ,

KE is 0 ,PE =mgRcos(alpha)

at point B

KE=mv² /2 , PE=mgRsin(beta)

applying conservation of energy

total energy initial = total energy final

mv² /2 = mgR{cos(alpha)- sin(beta)}................1

on resolving weight in two components will give one in direction opposite to normal reaction at point B...

so we can say that centripital force is provided by wsin(beta) only because normal reaction is 0 at this point as the body loses contact....

wsin(beta)=mgsin(beta)=mv² /R...............2

on solving 1 and 2 we get

3sin(beta)=2cos(alpha)

hence option c is correct....

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Q.A particle moves from rest at A on the surface of a smooth cylinder of radius r as shown.At B it leaves the cylinder.The equation relating alpha and beta is a.)3sin(alpha)=2cos(beta) b.)2sin(alpha)=3cos(beta) c.) 3sin(beta)=2cos(alpha) d.)2sin(beta)=3cos(alpha)

Q.A particle moves from rest at A on the surface of a smooth cylinder of radius r as shown.At B it leaves the cylinder.The equation relating alpha and beta is

a.)3sin(alpha)=2cos(beta)

b.)2sin(alpha)=3cos(beta)

c.) 3sin(beta)=2cos(alpha)

d.)2sin(beta)=3cos(alpha)

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