A particle is projected at an angle 60 degree,with speed 10sqrt3m/s from the Point A towards right.At the same time the wedge (HAVING ITS FOOT of inclination 30 degree at A) is made to move with speed 10sqrt3m/s towards right.Then the time after which the particle will strike with the wedge is(a)2s(b2sqrt3 m/s(c)4/sqrt3 m/s(d)none .............

dear Rajan

resolve the velocity of projectile

Ux= 10√3 COS60= 5√3

Uy=10√3 sin60=15

now you can see that horizontal velocity of wedge is more than the projectile hence they will not meet.

answer will be (d) none

All the best.

AKASH GOYAL

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Relative se solve kar, ban jayega.Wedge ko rest mein la,Wedge ki velocity projectile ke horizontal component ko opposite direction mein de, fir solve kr ...and ans is 2 sec