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a frictionless track ABCDE ends in a circular loop of radius "R". A body slides down the track from point "A" which is at height "h" = 5 cm. Maximum value of "R", for which the body successfully completes the loop is ??? What if the track is not frictionless ??
a frictionless track ABCDE ends in a circular loop of radius "R". A body slides down the track from point "A" which is at height "h" = 5 cm. Maximum value of "R", for which the body successfully completes the loop is ???
What if the track is not frictionless ??
Just at the topmost point of loop take centrifugal force eqal to mg.take out v^2 term from energy eqn.At 1st only p.e then at the topmost point of loop p.e.+ k.e.
the initial energy of the particle is mgh. It will complete the loop if it reaches the highest point on the loop which has a height of 2R. therefore by equating mgh =mg2R we get h=2R. R=2.5cm.
if there is frictional force the radius required will decrease even more depending on the coeff. of friction
Dear mohit,
At the top you have to take centrifugal force to be equal to mg and apply energy conservation law, You will get Maximum value of R=2 cm
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