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In fig below aconducting loop ADCA carrying current I and placed in a region of uniform magnetic field induction B0 . The part ADC forms a semicircle of radius R . The force on the semicircle part of the loop ADC is equal to
ans- 2RIB0
[url=http://img2.freeimagehosting.net/image.php?bb3bdedcad.jpg][img]http://img2.freeimagehosting.net/uploads/th.bb3bdedcad.jpg[/img][/url]

Shane Macguire , 12 Years ago
Grade upto college level
anser 1 Answers
Askiitians Tutor Team

To understand the force acting on the semicircular part of a conducting loop in a magnetic field, we need to consider a few fundamental principles of electromagnetism. The scenario involves a loop ADCA, where the segment ADC is a semicircle with radius R, carrying a current I in a uniform magnetic field B₀. Let's break this down step by step.

Magnetic Force on a Current-Carrying Conductor

When a current-carrying conductor is placed in a magnetic field, it experiences a force. This force can be calculated using the formula:

F = I (L × B)

Where:

  • F is the magnetic force.
  • I is the current flowing through the conductor.
  • L is the length vector of the conductor segment in the magnetic field.
  • B is the magnetic field vector.

Analyzing the Semicircular Segment

In our case, the semicircular segment ADC is crucial. The length of this segment can be calculated as:

L = πR

However, we need to consider that the direction of the magnetic force varies along the semicircle due to the curvature. The force on each infinitesimal segment of the semicircle can be expressed as:

dF = I (dL × B)

Here, dL is an infinitesimal length of the semicircle. The direction of dL changes as we move along the semicircle, which means the angle between dL and B also changes.

Calculating the Total Force

To find the total force on the semicircular part, we can integrate the force over the entire semicircle. However, due to symmetry, we can simplify our calculations. The net force will be directed perpendicular to the diameter of the semicircle, and we can consider the average effect of the magnetic field over the semicircle.

For a semicircular loop, the total force can be derived as:

F = 2RIB₀

This result arises because the effective length of the semicircle in the magnetic field contributes to the total force, and the factor of 2 accounts for the directionality and symmetry of the semicircular segment.

Conclusion

Thus, the force on the semicircular part of the loop ADC, when carrying a current I in a uniform magnetic field B₀, is indeed equal to 2RIB₀. This relationship highlights the interaction between electric currents and magnetic fields, a fundamental concept in electromagnetism that has numerous applications in technology and physics.

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