What is normal rection if a weight of 600kg is kept on tha inclined plane at 30sec.

Question

Piyush Kumar Behera · Answer

Assuming the question is about an incline plane at 30 degrees. We know that the weight is directed downwards of magnitude mg We can split this weight into two components, one towards the normal of the inclined plane and other parallel to the inclined plane. The component of weight along the normal to the inclined plane would be mg cos . As there is no net force along the normal. Hence the normal is mg cos = 600 x 9.8 x ( /2)

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What is normal rection if a weight of 600kg is kept on tha inclined plane at 30sec.

What is normal rection if a weight of 600kg is kept on tha inclined plane at 30sec.

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