Conducting circular loop of radius R carries a constant current I it is placed in a uniform magnetic field B such that BD is perpendicular to the plane of the loop the magnetic force acting on the loop is

The net attractive drive would be zero. 

In the event that we consider a point p and Q precisely inverse to each other on the circle. 

Lets expect that the constrain on a little part (straight wire) on dP of the circle is dF1 and same on dQ would be dF2. The course of attractive field is same at both the focuses yet the heading of current would be precisely inverse. Henceforth, the attractive constrain would cross out each other and the net drive on the entire wire would be zero.