Grade 12th passIntegral Calculus
Tell me answer step by step. Please sir how it can be solve. I do not know please help me.
1 Answer
Nandana
hi !
√(1+cos2x) = √(1+cos2 x -sin2 x)
=√(cos2 x + x2sin+cos2 x - x2sin)
=√(2cos2 x)
now,
√2 ∫sinx cosx dx
u = sinx
du = cosx dx
= √2 ∫ u du
= 1/√2 sin2 x + K
where , K is orbitary constant
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