## Guest

509 Points
12 years ago

1feet = 0.305m

550 feet = 0.305*550 meters

=167.75m = H (heigth)

now applying , V2 = U2 + 2aH

V = 0 , U = ? , H = 167.75  , a = -g

0 = U2 - 2*g*H

U2 = 3355

U = 57.9m/s

with this  initial velocity particle must be thrown

akash
24 Points
9 years ago
the function inside mod is +ve in interval [0,1] and -ve in (1,4] open the mod and do integration...
jagdish singh singh
173 Points
9 years ago
Sultan would you explain me how can you write here in LATEX form. I have enclose my LATEX code in [img]Latex code[/img] form . but could not get anything. Thanks
neeraj agarwal
34 Points
9 years ago
put x^2 + 1 as t 2x.x^2 ln(x^2+1)dx. hope you can do it now.
neeraj agarwal
34 Points
9 years ago
put 1/x as t . then partial fraction the function and solve
24 Points
9 years ago
Assume the integration to be I Now, add +1 and subtact 1 in the numerator then write 1-1 + sin^2(x)/(1+ sin^2(x) then write it as 1 - 1/(1 + sin^2(x) and then the value of 2I will be equal to integrate dx from 0 to 2 and the final answer will be one.
$\int \frac{x}{1-\sqrt{x+2}} \, dx=$$-\frac{1}{3} 2 (x+2)^{3/2}+2 \sqrt{x+2}-x+2 \log \left(1-\sqrt{x+2}\right)$