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it’s wrong you can see the derivate of ln(b²-cos²/a²-cos²) it s not a²-cos²/b²-cos²

it’s wrong you can see the derivate of ln(b²-cos²/a²-cos²) it s not a²-cos²/b²-cos²

Grade:10

1 Answers

Nandana
110 Points
4 years ago
hi..
   your thinking is ok , but  you forget to follow chain rule for differentiation
     you do like this ––
           d/dx {ln (f(x)/ g(x))} = 1/(f(x)*g(x)) , but you didn’t differentiate the functions containing ‘x’ !
              if you do so , again you need to use d/dx (u/v) formula & simplify it . you get correct answer !
 
                                                            thank you …!
 
         

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